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ap_physics_1 [2024/04/04 03:53] – mrdoughap_physics_1 [2024/04/20 05:37] (current) – external edit 127.0.0.1
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 ====== AP Physics 1 Study Guide ====== ====== AP Physics 1 Study Guide ======
 +  * Also refer to our [[AP Physics C Mechanics]] Study Guide, it has very similar topics for the most part and prettier formatting
 Credit goes to u/OldFlyingHat Credit goes to u/OldFlyingHat
   - 1D motion   - 1D motion
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         - Generally if pointed right its positive         - Generally if pointed right its positive
     - Acceleration     - Acceleration
-      - m/s^2+      - $\frac{m}{s^2}$
       - is a vector       - is a vector
       - points in the direction of the net force       - points in the direction of the net force
       - if velocity is changing acceleration is present       - if velocity is changing acceleration is present
-      - a= $ \Delta $ v/t or (vf-vi)/t+      - a= $ \Delta $ v/t or ($v_f$-$v_i$)/t
     - position vs time graph     - position vs time graph
       - y axis is x or position (m)       - y axis is x or position (m)
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       - Area under graph is change in velocity       - Area under graph is change in velocity
     - Kinematic formulas: ACCELERATION **HAS** TO BE **CONSTANT**     - Kinematic formulas: ACCELERATION **HAS** TO BE **CONSTANT**
-      - Vf=Vi+at +      {{:pasted:20240406-033657.png}}
-      - $ \Delta $X=vi*t+(1/2)at^2 +
-      - vf^2=vi^2+2a(Xf-Xi) +
-      - (vf+vi)/2=(xf-xi)/t+
     - Free Falling Object/ Flying Object     - Free Falling Object/ Flying Object
       - Acceleration is G (9.8m/s^2), but in a free falling occurrence the acceleration due to gravity is negative       - Acceleration is G (9.8m/s^2), but in a free falling occurrence the acceleration due to gravity is negative
-      - “Dropped” means Vi is 0+      - “Dropped” means $v_i$ is 0
         - Time after a drop is t=sqrt(2h/g)         - Time after a drop is t=sqrt(2h/g)
-      - At maximum height means Vf=0+      - At maximum height means $V_f$=0
  
   - 2D motion   - 2D motion
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       - Along x and y directions       - Along x and y directions
  
->   - Vx= Vcos(theta) deg+>   - $V_x$= Vcos($\theta$)
  
-  - Vy=Vsin(theta)+  - $V_y$=Vsin($\theta$)
  
   - DON’T FORGET SIGNS OF THE VECTORS YOU NERDS   - DON’T FORGET SIGNS OF THE VECTORS YOU NERDS
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       - Vf=Vi+(-9.8)t       - Vf=Vi+(-9.8)t
       - $ \Delta $X=vi*t+(1/2)(-9.8)^2       - $ \Delta $X=vi*t+(1/2)(-9.8)^2
-      - vf^2=vi^2+2(-9.8)(Xf-Xi)+      - $v_f^2=v_i^2+2(-9.8)(x_f-x_i)$
       - (vf+vi)/2=(xf-xi)/t       - (vf+vi)/2=(xf-xi)/t
     - Horizontal equation note: no horizontal acceleration     - Horizontal equation note: no horizontal acceleration
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